Author Topic: Armadillo question (Read 2682 times)

JohnP · « **on:** March 20, 2005, 06:23:14 AM »

Axis tilt is proportional to track diameter. When we locate the PAP using the armadillo, we match up the first oil line on the ball with one of the lines on the 'dillo. The center of these lines (the dashed line) is a full roller trace, or the full circumference of the ball. Then the lines are spaced at 1/2" increments. Since track diameter is proportional to track circumference, shouldn't there be an axis tilt associated with each of the lines on the 'dillo? Anyone using this to determine axis tilt? -- JohnP

Flip-Side-Wow · « **Reply #1 on:** March 20, 2005, 05:28:52 PM »

You could associate Mo's guidelines for axis tilt with the lines of the Armadillo. Here is his chart:

Arc length of the bowler's initial track Distance across initial "oil" track:

Less than 10" (More than 23.5 degrees of axis tilt)
Between 10" and 10-1/2" (Between 23.5 and 20 degrees of axis tilt)
Between 10-1/2" and 11" (Between 20 and 16.5 degrees of axis tilt)
Between 11" and 11-1/2" (Between 16.5 and 13.5 degrees of axis tilt)
Between 11-1/2" and 12" (Between 13.5 and 10 degrees of axis tilt)
Greater than 12" (Less than 10 degrees of axis tilt)

stanski · « **Reply #2 on:** March 20, 2005, 05:32:46 PM »

quote:
You could associate Mo's guidelines for axis tilt with the lines of the Armadillo. Here is his chart:

Arc length of the bowler's initial track Distance across initial "oil" track:

Less than 10" (More than 23.5 degrees of axis tilt)
Between 10" and 10-1/2" (Between 23.5 and 20 degrees of axis tilt)
Between 10-1/2" and 11" (Between 20 and 16.5 degrees of axis tilt)
Between 11" and 11-1/2" (Between 16.5 and 13.5 degrees of axis tilt)
Between 11-1/2" and 12" (Between 13.5 and 10 degrees of axis tilt)
Greater than 12" (Less than 10 degrees of axis tilt)

I think john knows this, but doesn't want to take the time to measure out the actual track length on all the lines of the armidillo. He wants someone to have a chart telling how long each line on the armidillo is. There should be a mathematical formula since you know what a full roller's actual track length is, but I really can't think of how you would do it right now.
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stanski

JohnP · « **Reply #3 on:** March 21, 2005, 08:59:09 AM »

kotm -- Not being lazy, there's not much math involved. The full roller track has a diameter of 13.5", and each 'dillo ring away from that reduces the diameter by 1", then relate to the standard diameter versus tilt chart, or multiply the number of rings by 6 2/3. But that seems too easy, I just wanted to be sure I'm not wrong, and that the 'dillo can be used this way. -- JohnP

Edited on 3/21/2005 9:59 AM

JohnP · « **Reply #4 on:** March 22, 2005, 08:38:41 PM »

I was back in the shop today and took a close look at my 'dillo. The first line away from the full roller line is only 1/4" away, so you would only count that as 1/2" difference in diameter. Then subsequent lines are in 1/2" increments. So a track that lined up three lines away from the full roller line would have a diameter of 11" (13 1/2 - 1/2 -2). -- JohnP

JohnP · « **Reply #5 on:** March 23, 2005, 08:31:17 PM »

To close out this topic --

I sent an E-mail to MoRich, since Mo Pinell developed the Armadillo. They said that the lines on the 'dillo do correlate to axis tilt and that they were considering issuing stickers to place on the 'dillo to show the degrees of axis tilt for each line. -- JohnP

Author Topic: Armadillo question (Read 2682 times)

JohnP

Armadillo question

Flip-Side-Wow

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stanski

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JohnP

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JohnP

Re: Armadillo question

JohnP

Re: Armadillo question