win a ball from Bowling.com

Author Topic: Can you determine what the weights will be for this "undrilled" ball?  (Read 2083 times)

Ric Clint

  • Hero Member
  • *****
  • Posts: 1681
The ball is undrilled and just has all the span lines on it as of right now.

The PIN is 3 1/8" from the CG
The TOP WEIGHT is 2.62oz

There's no marked MASS BIAS.

The PIN is 3/8" below my ring finger and 7/8" right of my grip line.

The CG is 1" right of my grip line and 1.5" below my midline (or is that midplane).


With the information I have listed here... can it be pre-determined what the ending weights will be after the ball is drilled and where the weight hole will need to be (if it needs one)?

And what kind of reaction can I expect from this ball?

I'm aiming for slight midlane and pretty good backend with a good bit of continuation.

Can my desired reaction be acheived with this drilling?


Thanks!





 

Mike Austin

  • Hero Member
  • *****
  • Posts: 2057
If I read correctly, you should have thumb and positive weight after drilling.  Don't know exactly how much of each, also depends on how deep you drill the holes and if you are using grips/slugs/inserts or not.

I probably would put the extra hole on a line from the center of your grip through the cg, 6-7 inches from the center of your span.

Should be fairly early and smooth.  Can be strong depending on surface and what ball it is.


--------------------
Mike Austin's Precision Pro Shop
Houston, TX
Drilling and Tech Advice BirdDogbowling.com

Check out bowlingballauctions.com !!!
A bowling alternative to Ebay, now open !!!

Driller to many "Stars" and Tony Melendez too!
Mike Austin's Bowling Dynamix Pro Shops
Inside Emerald Bowl
Inside Tomball Bowl
Track Pro Staff Member
Vise Grips Staff Member

TheDude

  • Hero Member
  • *****
  • Posts: 3170
sounds to me like a rev leverage type of layout but as previously stated, having to know your PAP an exact determination can't be made,

as for final static weights, as mike said you'd probably be heavy on thumb and side weight. a medium sized weight hole about 15/16 and two inches deep should bring you below 1 oz.
--------------------
Timothy @Juniors Pro-Shop
Staff Writer 7-10 Split Magazine,EGO Communications
Montreal, Quebec.

Vote No for USBC logos, and the effective ban of the X-hole. Vote in Orlando, June 05. Save Our X-Holes!
Timothy @Juniors Pro-Shops
LaSalle, Quebec-Located inside Pont Mercier Lanes.
Keep them honest!

Ebay store updated very often: http://stores.ebay.com/gumby3170?refid+store

LuckyLefty

  • Hero Member
  • *****
  • Posts: 17348
Using the gravity balance system from Lane#1 you could determine within about 1/4 ounce what your ending weights would be before weightholes if you knew your typical net weight removed.

Net weight is based on total weight and then adding back in thumb slugs(drilled out and finger inserts).

Where to put the weighthole to arrive at a final static could also be calculated.

I don't feel like doing it.

What reaction the ball will have will be determined by if you are a believer in ceegeenoomadeh.  A follower of core orientation theories.  (or should we say core axis angle).  Or a believer in....

Results will be clearly seen on the lanes however.

REgards,

Luckylefty
It takes Courage to have Faith, and Faith to have Courage.

James M. McCurley, New Orleans, Louisiana

shelley

  • Hero Member
  • *****
  • Posts: 9655
quote:
Ric

The thing to always remember where the grip is in relation to the pin is irrelevant.

The relevance is how far the pin is from the PAP. You do not show what the RG is or the diff. These are also important in ball motion.

Again where the pin is in relation to the grip is irrelevant as well as how far out the pin is from the CG.



Don't you determine static weights by dividing the ball into sections based on the location of the grip?  Take the line bisecting the fingers through the thumb hole to find side weight?  Divide the ball at the centerline to find finger/thumb weight?

I understand that PAP location relative to the PIN is a component of ball reaction, but simply for determining static weights, isn't the PAP irrelavent?

SH