So Symmetrics end up with their MB in the thumb hole or super close, right? So if you punch up an asymmetric with the MB in the thumb, wouldn't you treat the Pin-PAP the same as you would a symmetric?
To clarify we see Asymmetrics Pin-PAP differently when traversing between short and long pins, almost opposite of symmetrics. But if we put the MB in the same spot as where a symmetric ends up we equalized the third factor in the equation. So now a 5"x40 asymmetric would share the same thought process as a 5"x40 symmetric.
If I'm wrong, please tell me so and why.