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Author Topic: Pin position at 3-3/8 could be anywhere...  (Read 1352 times)

lefty50

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Pin position at 3-3/8 could be anywhere...
« on: August 10, 2004, 06:11:36 PM »
For any given PAP (I think my PAP is 4-1/4 and up 1/2, for example).

Let's say I'm taking a 3-3/8 inch pin distance. Any distance between two numbers can actually be an arc. It could be 3-3/8 straight up, or 3-3/87 at 90 degrees, or etc...

Why would I reference 3-3/8 as the maximum instability position if I know the pin placement is going to change the way the core lies down?

Signed,
Confused in San Diego.
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Signature? I don't need no stinking signature...
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livespive

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Re: Pin position at 3-3/8 could be anywhere...
« Reply #1 on: August 11, 2004, 09:20:26 AM »
No matter where on the 3-3/8 arc the pin lies the core is still at 45 degs
relative to the PAP.  That is where you instability comes from.

I'm no pro, but from what I have learned I think that is the reasoning.
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http://www.visionarybowling.com

Edited on 8/11/2004 9:31 AM
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JohnP

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Re: Pin position at 3-3/8 could be anywhere...
« Reply #2 on: August 11, 2004, 11:31:05 AM »
lefty50 - You are right.  If you draw a circle with a radius of 3 3/8" centered on your PAP, setting the pin at any point on that circle puts the core at a 45 degree angle.  That's why other criteria are used to further define the layout.  For example, cg (or mass bias) distance from PAP.  Or pin location in relation to finger holes.  --  JohnP
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