Author Topic: rg question? (Read 1037 times)

bowlingforfun · « **on:** May 19, 2004, 01:42:42 AM »

Does a ball with a RG of 2.50 an being a pearl coverstock differ from a ball with a Rg of 2.50 an being a solid or particle?

charlest · « **Reply #1 on:** May 19, 2004, 05:42:30 PM »

It is very hard to make such a comparison, even if the pearl and the solid were the same, except for the pearlization. Example: if 2 balls had the exact same core and one wasa pearl and one was asolid of Super-Flex (columbia), Activator (Brunswick), Big Bang (Ebonite) or Accu-Tread (Storm).

The difference in 2 balls' RG is better and more appropriately demonstrated when they have the same coverstock, be it solid resin, pearl resin, solid particle or pearl particle. And, even then, the RG differential (which usually translates into flare) can still affect the comaprison.

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"We get old too fast, and too late, smart."

Edited on 5/19/2004 5:41 PM

Juggernaut · « **Reply #2 on:** May 19, 2004, 06:39:40 PM »

R.G. (Radius of Gyration) is only a measurement of how far from the center of the ball the weight rotates.

If you have two balls with the same R.G. (as in your example) they will be the same rotationally. That is to say, that as far as the laws of physics is concerned, the two balls will generate the same power. Now, with the difference in coverstocks, they will tend to "spend" their energy in different ways.

In general, pearls tend to skid a little more and solids tend to roll a bit sooner. Solids and particles tend to handle a larger volume of oil than a pearl reactive.

In conclusion, if you have two identical ball with identical R.G. ratings drilled exactly alike, with the only differences being the covers, the differences in them will come strictly from the covers ability to handle oil.
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Just call me Darreyl, it's much easier to say!

Author Topic: rg question? (Read 1037 times)

bowlingforfun

rg question?

charlest

Re: rg question?

Juggernaut

Re: rg question?